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7x^2+64x-60=0
a = 7; b = 64; c = -60;
Δ = b2-4ac
Δ = 642-4·7·(-60)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5776}=76$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-76}{2*7}=\frac{-140}{14} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+76}{2*7}=\frac{12}{14} =6/7 $
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